Suppose you flip a coin twice. what is the probability that you get tails on the first flip and tail on the second flip?

The possibilities are HH TT HT TH so to get TT you have a 1/4 chance (25%)

You can count all the possibilities(sample space) for tossing a coin twice. Possibilities are: HH HT TT TH. So there are four possible outcomes and only one satisfies your demand i.e. HT. Hence probability of getting HT = 1/4.Now let’s solve it in more conceptual way. Suppose you toss a single coin then P(H) = 1/2 and P(T) = 1/2 assuming that coins is not biased. When you toss a coin twice, the second event is independent of first event. Therefore P(HT) = P(H).P(T) = 1/4.

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