Suppose a parabola has an axis of symmetry at x equals -8, a maximum height of 2, and passes through the point -7, -1. write the equation in vertex form

Vertex= (-8, 2)      (-7, -1)

y=a(x+8)²+2    Plug in the other point to find the "a"
-1=a(-7+8)²+2
-1-2=a(1)²
-3=a

Therefore, the equation in vertex form is y = -3(x+8)² + 2