What are the missing coefficients for the skeleton equation below? al2(so4)3(aq) + koh(aq) ® al(oh)3(aq) + k2so4(aq)

You have to balance the chemical equation:

Al2(SO4)3(aq) + KOH(aq) ---> Al(OH)3(aq) + K2SO4(aq)

To balance that equation you can start by balancing the SO4 radicals. That requires that you place a 3 coefficient before K2SO4 (in the right side):


Al2(SO4)3(aq) + KOH(aq) ---> Al(OH)3(aq) + 3K2SO4(aq)

Now write a 6 in front of KOH in the left side, to balance K

 
Al2(SO4)3(aq) + 6KOH(aq) ---> Al(OH)3(aq) + 3K2SO4(aq)

Now wirte a 2 before Al(OH)3 in the right side to balance the OH radicals


Al2(SO4)3(aq) + 6KOH(aq) ---> 2Al(OH)3(aq) + 3K2SO4(aq) 


Now you can verifiy that the equation is balanced.

The answer is: Al2(SO4)3(aq) + 6KOH(aq) ---> 2Al(OH)3(aq) + 3K2SO4(aq)