What is the time interval between the release of the ball and the time it reaches its maximum hieght? the acceleration gravity is 9.81m/s^2 and the maximum height is 4.4.m. neglect air resistance

We are going to use a kinematics equation and the knowledge that the maximum height of a projectile is achieved when the velocity in the y direction equals 0.

d = vt - (1/2)at²
d = -(1/2)at²
-2d/a = t²
t = √((-2 * 4.4)/(-9.81))
t = √0.897
t = 0.95s

tell him great job!

explanation:

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