Commuter train travels between two downtown stations. because the stations are only 1.18 km apart, the train never reaches its maximum possible cruising speed. during rush hour the engineer minimizes the travel interval δt between the two stations by accelerating for a time interval δt1 at a1 = 0.100 m/s2 and then immediately braking with acceleration a2 = -0.350 m/s2 for a time interval δt2. find the minimum time interval of travel δt and the time interval δt1.

Distance between stations = 1180 m

We have v = u+at

When the train is accelerating v = 0+0.100*δt1 = 0.1δt1

When the train is decelerating 0 = 0.1δt1 - 0.350*δt2

                                              So   δt1 = 3.5 δt2

Now we have s = ut +  

For the accelerating part

                 S1 = 0*δt1 +

For the decelerating part

                S2 =  

We have S1+S2 = 1180

32: from largest to smallest, this hierarchy includes eons, eras, periods, epochs, and ages.

33: answer is c

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increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.