Determine the freezing point of a solution that contains 0.31 mol of sucrose in 175 g of water

ΔT= T (solvet freezing point)-T (solution) =T(water freezing point)-T(solution)
ΔT =0⁰C - T(solution)

ΔT=

molality =(number mol solute)/kg solvent = 0.31mol/0.175 kg =(0.31/0.175)m
K(f water)=1.86⁰C/m
ΔT=1.86⁰C/m*(0.31/0.175)m=3.29⁰C
T(solution) =0⁰C - 3.29⁰C =3.29⁰C 

Ithe undersigned only for use your own email and delete any and copies and of the itself and to be there is a good timewhat does a decrease in temperature indicate about the molecules in a sample of liquid water? decreased chemical energy of the moleculesdecreased kinetic energy of the moleculesincreased chemical energy of the moleculesincreased kinetic energy of the moleculeshow does a sample of helium at 15 â°c compare to a sample of helium at 215 k? the helium at 15 â°c has a higher average kinetic energy than the sample at 215 k.the helium at 15 â°c has lower nuclear energy than the sample at 215 k.the helium at 15 â°c has slower-moving atoms than the sample at 215 k.the helium at 15 â°c has smaller atoms than the sample at 215 k.

C. definite shape, definite volume. that is a solid.