Determine the freezing point of a solution which contains 0.31 mol of sucrose in 175 g of water. kf = 1.86ï°c/m

Freezing point depression is a colligative property.

The formula that rules it is:

ΔT f = Kf * m

Where m is the molality of the solution => m = moles of solute / Kg of solvent

=> m = 0.31 mol / 0.175 kg = 1.771 m

And kf = 1.86 °C/m

=> ΔTf = 1.771 m * 1.86 °C / m = 3.3 °C

 => Freezing point of the solution = normal freezing point of water - 3.3 °C = 0 - 3.3°C = - 3.3°C.

-3.3 °C

Woah that’s a lot to read xd i’ll try though. i’ll get back t you if. i know the andwer

Ans. : frostbite is when exposure to cold temperatures causes freezing to the skin or other tissues. it most commonly affects the hands, feet, and face. the longer areas are exposed to cold, typically the worse the frostbite. the water temperature used for rewarming a frostbitten part should be : (102 -105) f degrees.