Chemistry, 24.07.2019 01:30, Boayerik

What is the concentration of the unknown h3po4 solution? the neutralization reaction ish3po4(aq)+3naoh(aq)→3h2o(l)+na3po 4(aq) -g, com?

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Answers

First, we need to get moles of NaOH:

when moles NaOH = volume * molarity

= 0.02573L * 0.11 M

= 0.0028 moles

from the reaction equation:

H3PO4(aq) + 3NaOH → 3 H2O(l) + Na3PO4(aq)

we can see that when 1 mol H3PO4 reacts with→ 3 mol NaOH

∴ X mol H3PO4 reacts with → 0.0028 moles NaOH

∴ moles H3PO4 = 0.0028 mol / 3 = 9.4 x 10^-4 mol

now we can get the concentration of H3PO4:

∴[H3PO4] = moles H2PO4 / volume

= 9.4 x 10^-4 / 0.034 L

= 0.028 M

answered: rishamoore

The concentration of the unknown H₃PO₄ solution : 0.0344 M

Further explanation

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.

An acid-base titration there will be a change in the pH of the solution.

From this pH change a Titration Curve can be made which is a function of acid / base volume and pH of the solution

Acid-base titration formula

Ma. Va. na = Mb. Vb. nb

Ma, Mb = acid base concentration

Va, Vb = acid base volume

na, nb = acid base valence

We complete the possible questions

A 34.00 mL sample of an unknown H₃PO₄ solution is titrated with a 0.130 M NaOH solution. The equivalence point is reached when 26.98 mL of NaOH solution is added.

H₃PO₄ is a weak acid with valence 3 because it releases 3 H + atoms

H₃PO₄ -> 3H⁺ + PO₄⁻

NaOH is a strong base with valence 1 because it releases 1 OH- ions

NaOH ---> Na⁺ + OH-

We input the numbers into the formula:

M1.V1 n1= M2.V2 .n2

1 = H₃PO₄

2 = NaOH

M1.34 ml .3 = 0.130. 26.98 ml.1

M1 = 0.0344

So the molarity of the H₃PO₄ solution = 0.0344 M

Learn more

the best tool to find the volume of that she needs to neutralize the acid

link

Determine the endpoint of the titration.

link

acid-base

link

Identify the acids and the bases

link

endpoint titration

link

answered: Guest

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

$^{m}_{4}x$ and $^{m}_4y$

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

$^{m}_{5}x^{-}$

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be $^{9}_{5}be^{-}$ and $^{9}_{4}be$ .

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.

answered: Guest

$\frac{239}{94}pu+\frac{1}{0}n ====> \frac{y}{z}x+\frac{134}{54}xe+3\frac{1}{0}$

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137 subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54 subtract 54 from both sides.

40 = z

answer

$\frac{103}{40}x=\frac{103}{40}zr$