Chemistry, 26.07.2019 00:00, emcarrell

How many grams of sucrose must be added to 552 grams of water to give a solution?

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1.35x10^-5 grams of sucrose must be added to produce a solution with vapor pressure of 15.5 mmHg.
Solution:
We can use the Raoult's law to get the mole fraction of water Xsolvent present in the solution:
Psolution = Xsolvent Posolvent
(17.5 mmHg - 2.0 mmHg) = Xsolvent (17.5 mmHg)
Xsolvent = 0.886

We use the molar mass of water to compute for its number of moles:
moles of solvent = (552 g H2O)(1 mol H2O / 18.015 g H2O)
= 30.64 mol H2O

From the mole fraction of the water given by
Xsolvent = moles of solvent / sum of moles of solution
= moles of H2O/ (moles of sucrose + moles of H2O)
0.886 = (30.64 mol) / (moles of sucrose + 30.64 mol)

we can solve for the number of moles of sucrose:
moles of solute = (30.64 mol / 0.886) - 30.64 mol = 3.94 mol sucrose

We can now calculate for the mass of sucrose using its molar mass:
mass of sucrose = (3.94 mol sucrose)(342.3 g sucrose / 1 mol sucrose)
= 1.35x10^-5 grams

answered: Guest

the answer is 1 i believe

answered: Guest

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

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