What is the theoretical yield of h2o if 130 g of h2o is produced from 18 g of h2 and an excess of o2?

You are given 130 grams of H20 and 18 grams of H2. You are required to get the theoretical yield of H2O. Before anything else, you should know the chemical equation of H20 and H2. The balanced chemical reaction is 2H2 + O2 -> 2H2O. The molar mass of H2O is 18 grams per mole and the 2 grams per mole for H2.  

18g H2 (1 mol H2/2 g H2)(2 mol H2O/ 2 mol H2)(18 g H2O/1 mol H2O) = 162 g H2O  
Thus the theoretical yield for 18g H2 is 162g H2O.  

I’m not sure what your trying to say here.. can you clarify again?