How many moles of oxygen (o2) are present in 33.6 l of the gas at 1 atm and 0°c?

1.500 moles of O₂

Explanation:

At the pressure of 1 atm, the gas can be considered an ideal gas, so we can use the ideal gas equation:

PV = nRT

Where P is the pressure in atm, V is the gas volume in L, n is the number of moles, R is the gas constant = 0.082 atm.L/mol.K, and T is the temperature in K, so T = 0ºC + 273.15 = 273.15 K.

1x33.6 = nx0.082x273.15

22.3893n = 33.6

n = 1.500 moles of O₂