Chemistry, 10.05.2021 03:50, NobleWho

88 mL of 0.2M NaCI is reacted with excess lead(I1)nitrate, calculate the grams of PbCl2 produced. 2NaCI(aq) + Pb(NO3) (aq) PbCl2(s) + 2NaNO3(aq)

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88 mL of 0.2M NaCI is reacted with excess lead(I1)nitrate, calculate the grams of PbCl2 produced....