O y=0.048x^2 – 2494
Mathematics, 10.11.2020 22:10, peno211
Which quadratic equation models the main cable
of the bridge correctly?
O y=0.048x^2 – 2494
y = 0.048x^2-6
y = 0.0048(x - 50)^2 + 6
y=0.0048(x - 6)^2 + 50
Answers: 3
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If 5x - 2 = -12, then x = a) -50 b) -4.4 c) -2.8 d) -2
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Which quadratic equation models the main cable
of the bridge correctly?
O y=0.048x^2 – 2494
O y=0.048x^2 – 2494
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