Achemist uses 0.25 l of 2.00 m h2so4 to completely neutralize a 2.00 l of solution of naoh. the balanced chemical equation of the reaction is given below. 2naoh + h2so4 na2so4 + 2h2o what is the concentration of naoh that is used?

The molarity of the NaOH solution is 0.5 M.

Explanation:

Moles of in 0.25 L of 2.00 M solution:

Moles of = 2.00 mol/L × 0.25 L = 0.5 moles

Moles of in 2.00 L of an unknown Molarity :

1 mole gives 2 moles of ions.

Then 0.5 mole will give: 0.5 mol × 2 = 1.0 mol

1.0 mol of will neutralize the 1.0 mol of ions.

Moles of = Moles of = 1.0 moles

1 mol of are produced by 1 mol of NaOH

The 1 mole of will be produced from = 1 mol of NaOH

The molarity of the NaOH solution is 0.5 M.

it is stable as it is in group 0 which have full outer shells of electrons