The value of ksp for silver carbonate, ag2co3, is 8.10×10−12. calculate the solubility of ag2co3 in grams per liter.

0.0349 g/L  

Explanation:  

Let s = the molar solubility.  

                     Ag₂CO₃(s) ⇌ 2Ag⁺(aq) + CO₃²⁻(aq); = 8.10 × 10⁻¹²

E/mol·L⁻¹:                                2s                 s  

=[Ag⁺]²[CO₃²⁻] = (2s)²×s = 4s^3 = 8.10 × 10⁻¹²  

the correct answer is:

a. formation of precipitation