Calculate the solubility (in g/l) of silver carbonate in water at 25°c if the ksp for ag2co3 is 8.4 x 10-12, a) 8.0 x 10-4 g/l b) 3.5 x 10-2 g/l c)4.4 × 10-2g/l d) 5.6 x 10-2 g/l

S = 5.6 E-2 g / L

Explanation:

⇒         S                 2S       S

⇒ Kps = 2S*S = 2S² = 8.4 E-12

⇒ S² = 8.4 E-12 / 2

⇒ S² = 4.2 E-12

⇒ S = √4.2 E-12

⇒ S = 2.05 E-6 mmol / mL

⇒ S = 2.05 E-6 mmol / mL * 0.001 mol / mmol * 275.7453 g Ag2CO3 / mol * 1000mL / L

⇒S = 5.651E-2 g / L

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

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