What volume of oxygen gas, in milliliters, is required to react with 0.640 g of so2 gas at stp?

11.2 ml
22.4 ml
112 ml
224 m

Answer : The correct option is, 112 ml

Solution : Given,

Mass of = 0.640 g

Molar mass of = 64 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of oxygen gas.

The balanced chemical reaction will be,

From the reaction, we conclude that

As, 2 moles of react with 1 mole of gas

So, 0.01 moles of react with mole of gas

Now we have to calculate the volume of oxygen gas.

As, 1 mole of oxygen gas contains 22400 ml volume of oxygen gas

So, mole of oxygen gas contains volume of oxygen gas

Therefore, the volume of oxygen gas is, 112 ml

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