How many grams of cif3 form when .204 moles of f2 react with excess cl2?
the answer must be sold with dimensional analysis.

The reaction equation:
2Cl₂ + 3F₂ → 2ClF₃

Moles of F₂ = 0.204
Moles of ClF₃ = 2/3 x 0.204
= 0.136 mole

Mass = moles x Mr
= 0.136 x (35.5 + 19 x 3)
= 12.58 grams of ClF₃ will be formed.

The answer is d.potassium

It is a mixture. simply put, a compound must be pure, that is, of only one chemical structure and composition. a mixture is made of different chemical substances (i.e. elements, molecules, compounds) that are not chemically bonded to each other, but instead physically grouped together, as in the case of gasoline (a homogeneous solution).