Chemistry, 25.03.2021 05:10, mahkitheking16

The equilibrium constant, K, for the following reaction is 2.90x10-2 at 1.15x103K. 2503(g) =2502(g) + O2(g) If an equilibrium mixture of the three gases in a 15.3 L container at 1.15*10PK contains 0.326 mol of S03(g) and 0.332 mol of SO2, the equilibrium concentration of O2 is M.

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The equilibrium constant, K, for the following reaction is 2.90x10-2 at 1.15x103K. 2503(g) =2502(g)...