What are the correct coefficients for the unbalanced equation below? P4 +02 → P2O5

A)1,1,1
B) 1,3,1
C)1,5, 2
D)2,1,2
E)none of the above

PLEASE EXPLAIN WHY! I will mark the brainliest!

C; 1, 5, 2

Explanation:

First, we do atom inventory:

Think of the arrow as a divider

On the left side, we have 4 phosphorus and 2 oxygens

On the right side, we have 2 phosphorus and 5 oxygens

Now we try to balance:

To make it easier, we want to try and make the 5 oxygens get to an even number so, we put a 2 in front of the P2O5 which makes it 2P2O5

Since we put a 2 in front of the P2O5, we have to multiply our phosphorus and oxygen on the right side by 2, which brings us to now have 4 phosphorus and 10 oxygens.

So now the oxygens are unbalanced.

To balance the oxygens, we put a 2 in front of the O2 located on the left side which makes us multiply our oxygen by 5, making it now 10.

Final result:

We end up having P4 + 5O2 = 2P2O5

(1, 5, 2)

if you mean hydrogen and oxygen then water is the product

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