For the reaction magnesium plus hyrdogen chloride yeilds hydrogen and magnesium chloride, calculate the percent yield of magnesium chloride if 100. G of magnesium react with excess hydrochloric acid to yield 330. G of magnesium chloride

Percentage yield of MgCl₂ = 83.4%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Mg + 2HCl —> MgCl₂ + H₂

Next we shall determine the mass of of Mg that reacted and the mass of MgCl₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of Mg = 24 g/mol

Mass of Mg from the balanced equation = 1 × 24 = 24 g

Molar mass of MgCl₂ = 24 + (35.5×2)

= 24 + 71

= 95 g/mol

Mass of MgCl₂ from the balanced equation = 1 × 95 = 95 g

SUMMARY:

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgCl₂.

Next, we shall determine the theoretical yield of MgCl₂. This can be obtained as follow:

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgCl₂.

Therefore, 100 g of Mg will react to produce = (100 × 95)/24 = 395.83 g of MgCl₂.

Thus, the theoretical yield of MgCl₂ is 395.83 g

Finally, we shall determine the percentage yield of MgCl₂. This can be obtained as follow:

Actual yield of MgCl₂ = 330 g

Theoretical yield of MgCl₂ = 395.83 g

Percentage yield of MgCl₂ =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 330 / 395.83 × 100

Percentage yield of MgCl₂ = 83.4%

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.