Which points are a distance of 5 units from (2, 3) if ? (7, 3) (–1, –1) (0, 3) (2, 8) (−7, 6)

(7, 3), (–1, –1) and (2, 8) are at a distance of  units from (2, 3).

Step-by-step explanation:

We know that the formula of distance is given by:

Distance =

So substituting the given points points to check which points are at a distance of 5 units from .

1. (2, 3) and (7, 3):

2. (2, 3) and (–1, –1):

3. (2, 3) and (0, 3):

4. (2, 3) and (2, 8):

5. (2, 3) and (-7, 6):

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.