N2 + 3H2 → 2NH3 How many moles of NH3 could you make with 4.2021 g of N2?

I need this like rn pls .

Moles of NH3 = 0.3 moles

N2 + 3H2 → 2NH3

4.2021 g of N2

Required

moles of NH3

Solution

mol N2 :

= 4.2021 g : 28 g/mol

= 0.15

From the equation, mol NH3 :

= 2/1 x mol N2

= 2/1 x 0.15

= 0.3 moles

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."