During the reaction P4 + 5O 2 P4 O10, 1.5 moles of product was made in 30 seconds. What is the rate of reaction? a) 0.011 g/min
b) 210 g/min
c) 380 g/min
d) 850 g/min

850g/min

Explanation:

The reaction expression is given as:

      P₄  +  5O₂   →   P₄O₁₀

Given that:

Number of moles of product  = 1.5moles

Time  = 30s = 0.5min

Unknown:

The rate of the reaction  = ?

Solution:

Convert the moles given to mass of the product.

     So;

     Mass of product  = number of moles x molar mass

Molar mass of P₄O₁₀   = 4(31) + 10(16)  = 284g/mol

    Mass of product  = 1.5moles x 284g/mol  = 426g

So;

 Reaction rate  =   =   = 850g/min

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when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol