If a compound has a molar mass of 180 g/mol and its empirical formula is ch2o, what is its molecular formula?

The molecular formula of a compound that has a molar mass of 180 g/mol and its empirical formula is CH2O is

C6H12O6

calculation

step 1: Given the empirical formula divide the gram molecular mass with

empirical formula mass

that is empirical formula mass (cH2O) = 12+2+16 = 30 g/mol

gram molecular mass = 180 g/mol

= 180 g/mol/30 g/mol = 6

step 2: multiply each subscripts in the empirical formula by 6

that is [CH2O]6

molecular formula is therefore= C6H12O6

the answer to your question is c.

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