A photon has an energy of 2.34x10-28 J. What is its frequency?

f = 3.53×10⁵ s⁻¹

Explanation:

Given data:

Energy of photon = 2.34×10⁻²⁸ J

Frequency = ?

Solution:

h = 6.63 ×10⁻³⁴

Formula:

E = hf

2.34×10⁻²⁸ J = 6.63 ×10⁻³⁴ × f

f = 2.34×10⁻²⁸ J /  6.63 ×10⁻³⁴ Js

f = 0.353×10⁶ s⁻¹

f = 3.53×10⁵ s⁻¹

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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