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![\begin{array}{rcl}\text{pH} & = & \text{pK}_{\text{a}} + \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\& = &4.75 +\log \left(\dfrac{0.05}{0.10}\right )\\\\& = & 4.75 + \log0.50 \\& = & 4.75 - 0.30\\& = &4.45 \\\end{array}](/tpl/images/0721/7728/32461.png)
![\rm [H_{3}O^{+}] = 10^{-pH} = 10^{-4.45} = 3.56 \times 10^{-5}\, mol/L](/tpl/images/0721/7728/79adc.png)
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