Two atoms of the same element approach each other with the velocities shown. v1. v1> v2. After the collision, which is most likely?

a. Atom #1 and atom #2 will move away with the same speed, which is some speed between v1 and v2.
b. Atom #1 will move away with speed v1, and atoms #2 will move away with speed v2
c. Atom #2 will stop and atom #1 will move away with speed v2+v1
d. Atom #1 will stop and atom #2 will move away with speed v2+v1
e. Atom #2 will move away with speed v1, and atoms #1 will move away with speed v2
f. Atom #1 and atom #2 will move away with the same speed, which is calculated as v1-v2

look at the !

pleaze mark brainliest!

thats a little if u want the answer just look it up on google thats what i do haha : )

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.