The generic metal hydroxide M(OH)2 has Ksp = 7.25×10−12. (NOTE: In this particular problem, because of the magnitude of the Ksp and the stoichiometry of the compound, the contribution of OH− from water can be ignored. However, this may not always be the case.)

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The generic metal hydroxide M(OH)₂ has Ksp = 7.25 × 10⁻¹². (NOTE: In this particular problem, because of the magnitude of the Ksp and the stoichiometry of the compound, the contribution of OH⁻ from water can be ignored. However, this may not always be the case.)

What is the solubility of M(OH)₂ in pure water?  Express your answer with the appropriate units.

Answer : The solubility of M(OH)₂ in pure water is,

Explanation :

The equilibrium chemical reaction will be:

The solubility constant expression for this reaction is:

Let the solubility be, 'x'

     x                 x                 2x

Now put all the given values in this expression, we get:

Thus, the solubility of M(OH)₂ in pure water is,

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