What is the energy of light with a wavelength of 468 nm? (The speed of light
in a vacuum is 3.00 x 10^8m/s, and Planck's constant is 6.626 x 10^-34J·s.)
A. 2.35 x 10^27J
B. 4.25 x 10^-28mJ
C. 2.35 x 10^18J
D. 4.25 x 10^-19J

The answer for the problem is explained below.

The option for the answer is "D".

Therefore the energy of the light is  4.25 × 10^-19 J

Explanation:

Given:

wavelength (λ) = 468 nm = 468×10^-9 m

speed of light (c) = 3.00 x 10^8m/s

Planck's constant is 6.626 x 10^-34J·s

To solve:

energy of light (E)

We know,

E =(h×c) ÷ λ

E = ( 6.626 x 10^-34 ×  3.00 x 10^8) ÷ 468×10^-9

E = 4.25 × 10^-19 J

Therefore the energy of the light is  4.25 × 10^-19 J

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally