What is the change in temperature is 42g of water at 50°C absorbs 985J of heat energy

ΔT = 5.6°C

Explanation:

Given data:

Heat added = 985 j

Mass of water = 42 g

Initial temperature = 50°C

Change in temperature  = ?

Solution;

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water = 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values.

985 j = 42 g ×4.18 j/g.°C × (Final temperature - initial temperature)

985 j = 42 g ×4.18 j/g.°C × (T2 - 50°C)

985 j = 175.56  j/°C × (T2 -50°C)

985 j / 175.56  j/°C = T2 - 50°C

5.6°C + 50°C = T2

T2 = 55.6°C

Change in temperature = ΔT = Final temperature - initial temperature

ΔT = 55.6°C - 50°C

ΔT = 5.6°C

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