What is the molarity of an hcl solution if 50.0 ml is neutralized in a titration by 40.0 ml of 0.400 m naoh?

a.) 0.200 m
b.) 0.500 m
c.) 0.280 m
d.) 0.320 m

M ( HCl ) = ?

V ( HCl) = 50.0 mL in liters :  50.0 / 1000 => 0.05 L

M ( NaOH ) = 0.400 M

V ( NaOH ) = 40.0 mL / 1000 => 0.04 L

number of moles ( NaOH) :

n = M x V

n = 0.400 x 0.04 => 0.016 moles of NaOH:

HCl + NaOH = NaCl + H₂O

1 mole  HCl 1 mole NaOH
? mole HCl  0.016 moles NaOH:

moles HCl = 0.016 x 1 / 1

= 0.016 moles of HCl

M ( HCl ) = n / V

M ( HCl ) = 0.016 / 0.05

= 0.320 M

Answer D

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