I’ll really appreciate it! part a- explain why the x-coordinates of the points where the graphs of the equations y=2^-x and y=8^x+4 intersect are the solutions of the equation 2^-x=8^x+4 part b- make tables to find the solution to 2^-x = 8^x+4. take the integer values of x between -3 and 3. part c- how can you solve the equation 2^-x=8^x+4 graphically? i need this asap and i’d be extremely , i’ll give you brainliest!

Part A- Explain why the x-coordinates of the points where the graphs of the equations y=2^-x and y=8^x+4 intersect are the solutions of the equation 2^-x=8^x+4

Because the intersection point has the a unique pair of (x,y) coordinates; such coordinates x,y belong to both equations.

Part B- Make tables to find the solution to 2^-x = 8^x+4. Take the integer values of x between -3 and 3.

x        2^ (-x)                 8^(x + 4) < this is how I understand the right side

- 3      2^3 = 8               8^(1) = 8

- 2      2^2 = 4               8^(2) = 64

- 1     2^1 = 2                8^(3) = 512

 0      2^0 = 1                8^(4) =  4,096

=> solution x = - 3

You can continue filling the table for x =1, x = 2 and x = 3, but the solution is already stated x = - 3.

Part C- How can you solve the equation 2^-x=8^x+4 graphically?

Draw the graphs of both equation is the same coordinate system and the solution will be the point where the two curves intersect each other.

The year before the 10s so it was like when caveman were alive