A pure aluminium block with a mass of 10g is heated so that its temperature from 20C to 50C. The specific heat capacity of aluminium is 8.99 x 10^-1 J/gK. which expression gives the heat energy change in kJ

0.2697kj

Explanation:

H,=mcΔt

H= 10*0.899(323-293)

H=10*0.899*30

H=269.7j

H= 0.2697kj

the answer is d : ) have a good da

air

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