Apercent composition analysis yields 32.37% sodium, 22.57 sulfur and 45.05% oxygen what is the empirical formula for the compound

Na₂SO₄

Explanation:  

Assume that you have 100 g of the compound.  

Then you have 32.37 g Na, 22.57 g S, and 45.05 g O.  

1. Calculate the moles of each element.

Moles of Na = 32.37 × 1/22.99  =   1.408   mol Na

Moles of S    = 22.57 × 1/32.06  = 0.7040 mol S

Moles of O   = 45.05 × 1/16.00   = 2.816    mol O

2. Calculate the molar ratios.  

Divide all values by the smallest number.

Na: 1.408/0.7040   = 2.000

S:  0.7040/0.7040 = 1

O: 2.816/0.7040    = 4.000

3. Determine the empirical formula

Round off all numbers to the closest integer.  

Na: 2

S:   1

O:  4

The empirical formula is Na₂SO₄.

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.