How many atoms of Hydrogen in the reactants of the following equation?

3Ba(OH)2 + 2Na3PO4 --> Ba3(PO4)2 + 6NaOH

6
5
4
3
Remember that the coefficient at the front of the compound must be multiplied by any subscript . If there is no subscript, it is multiplied by one. For example, the coefficient 3, in front of Barium hydroxide, must be multiplied by the subscript "2" to find the number of Hydrogen atoms, as well as to find the number of Oxygen atoms, since the "2" subscript applies only to the atoms in the parentheses.

6 atoms of H in the reactants

Explanation:

3Ba(OH)₂ + 2Na₃PO₄ --> Ba₃(PO4)₂ + 6NaOH

In reactant side you have 3 moles of Ba(OH)₂

- Ba(OH)₂

- Ba(OH)₂

- Ba(OH)₂

Therefore you have 6 OH⁻. You have 6 H on it.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole