Write the concentration equilibrium constant expression for this reaction.

cu(s) + 2ag+(ag) -> cu2+(aq) + 2ag(s)

K = [Cu2^+] / [Ag^+]^2

Explanation:

The equilibrium expression written for a system in equilibrium must take into account the balanced equation for the reaction and the phases (solid, liquid, gas, or dissolved) of each species involved in the reaction.

aA + bB ⇆ cC + dD

Kc = [C]^c + [D]^d / [A]^a + [B]^b

"[ ]" - concentration of the species (moles per liter or molarity)

"a, b, c, d" - coefficients used to balance the equation

"c in Kc" - indicates that the value of K is determined using the concentrations of each species

There are two cases when a species is not shown in the equilibrium expression:  when it is a solid and when it is a pure liquid or solvent.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.