Which solution is the most concentrated? each choice refers to the same solute and solvent. a) 2.4 g solute in 2 ml solution b) 2.4 g solute in 5 ml solution c) 20 g solute in 50 ml solution d) 30 g solute in 150 ml solution e) 50 g solute in 175 ml solution

A

Explanation:

The units for concentration can be g/ml (grams per milliliter)

Hence we will need to calculate the concentration for each option before making a decision:

A = 2.4 / 2  = 1.2 g/ml

B = 2.4 / 5  = 0.48 g/ml

C = 20 / 50  = 0.4 g/ml

D = 30 / 150  = 0.2 g/ml

E = 50 / 175  = 0.286 g/ml

Using these values, the concentration with the highest value will give us the most concentrated solution, which in this case is option A at 1.2 g/ml.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g