The rate of reaction for a hypothetical reaction was found to be 0.62 mol/l*s at 6°c. what would be the rate at   46°c?

9.92 mol/L*s

Explanation:

Given data:

Rate of reaction = 0.62 mol/L*s

Temperature = 6°C

Rate of reaction at 46°C = ?

Solution:

There are 10 increase in four time of given temperature.

6+10 = 16

16+ 10 = 26

26+10 = 36

36=10 = 46

According to thumb rule,

By doubling the reaction four time the rate will be,

0.62 mol/L*s ×2⁴

0.62 mol/L*s × 16

9.92 mol/L*s