Abuffer can be prepared by mixing two solutions. determine if each of the following mixtures will result in a buffer solution or not.1) mixing 100.0 ml of 0.1 m hf with 100.0 ml of 0.05 m mol kf [ select ] ["yes, it will result in a buffer solution.", "no, it will not result in a buffer solution."] 2) mixing 100.0 ml of 0.1 m nh3 with 100.0 ml of 0.1 m nh4br [ select ] ["yes, it will result in a buffer solution.", "no, it will not result in a buffer solution."] 3) mixing 100.0 ml of 0.1 m hcn with 100.0 ml of 0.05 m koh [ select ] ["no, it will not result in a buffer solution.", "yes, it will result in a buffer solution."] 4) mixing 100.0 ml of 0.1 m hcl with 100.0 ml of 0.1 m kcl [ select ] ["yes, it will result in a buffer solution.", "no, it will not result in a buffer solution."] 5) mixing 100.0 ml of 0.1 m hcn with 100.0 ml of 0.1 m koh [ select ] ["yes, it will result in a buffer solution.", "no, it will not result in a buffer solution."]

The answers are in the explanation

Explanation:

A buffer is the mixture of a weak acid with its conjugate base or vice versa. Thus:

1) Mixing 100.0 mL of 0.1 M HF with 100.0 mL of 0.05 M mol KF. Will result in a buffer because HF is a weak acid and KF is its conjugate base.

2) Mixing 100.0 mL of 0.1 M NH₃ with 100.0 mL of 0.1 M NH₄Br. Will not result in a buffer because NH₃ is a strong base.

3) Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.05 M KOH. Will result in a buffer because HCN is a weak acid and its reaction with KOH will produce CN⁻ that is its conjugate base.

4) Mixing 100.0 mL of 0.1 M HCl with 100.0 mL of 0.1 M KCl Will not result in a buffer because HCl is a strong acid.

5) Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.1 M KOH Will not result in a buffer because each HCN will react with KOH producing CN⁻, that means that you will have just CN⁻ (Conjugate base) without HCN (Weak acid).

I hope it helps!

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i believe the answer is true.