Section: 6.2
22) in the reaction shown, what is the mole ratio that would be used to determine the number of
moles of h2 that would be produced when 3.5 moles of aici3 are produced?
3.smols ali1 c1: 3
2 al + 6 hcl → 2 aici3 + 3 h2
a1 26.98 el 35.45
a) 2 moles a
3 moles hc1
2 moles aic 13
b) 3 moles h2
3.5 moles aic 13
c) 3 moles h2
3 moles h2
d) 2 moles aic 13

2b2t

explanation:

2b2t

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2