One way to experimentally measure the heat capacity of a styrofoam cup calorimeter would be to melt a known mass of ice in warm water and measure hte temperature change. use the data below to determine the experimental heat capacity of the calorimeter. use the literature heat of fusion for ice in your calculations. assume the ice added is at 0.00 c. mass of ice added: 17.69gmass of water in calorimeter: 98.67gt-initial of water: 28.7t-final of water after melting ice: 12.9c

4.88 Cals per degree celsius

Explanation:

We have taken heat of fusion of ice = 80 cals / g

We have taken speciic heat of water = 1 cal/g per degree celsius

In this experiment ,  let the heat capacity of calorimeter be X.

Heat gained by ice

heat gained in melting + heat gained in getting warmed

= mass x latent heat + mass x specific heat x rise in temperature

= 17.69 x 80 + 17.69 x 1 x ( 12.9 - 0 )

= 1643.4 Cals

Heat lost by water

=  mass x specific heat x fall in temperature

98.67 x 1 x ( 28.77 - 12.9 )

= 1565.89 Cals

Heat lost by calorimeter

heat capacity x fall in temperature

X x ( 28.77 - 12.9 )

Heat gained = heat lost

1643.4 = 1565.89 +15.87X

X = 4.88 Cals per degree celsius

the objects have the same charge is correct.

nathan lee