When 25.4 g nano3 is dissolved in water to make 1250 ml of solution, what is the molarity of the solution?

Molarity = 0.24 mol/L

Explanation:

Given data:

Mass of NaNO3 = 25.4 g

Volume of solution = 1250 mL

Molarity = ?

Solution:

Molarity of solution is equal to the number of moles of solute divided by volume of solution in litter.

Formula:

Molarity = number of moles / volume in L

First of all we will convert the volume in litter.

1 L = 1000 mL

1250 / 1000 = 1.25 L

Now we calculate the moles of NaNO3 in present in 25.4 g.

Number of moles = mass / molar mass

Molar mass of NaNO3 = (23 + 14+ 16×3) = 85 g/mol

Number of moles =  25.4 g / 85 g/mol

Number of moles = 0.299 mol

Now we will calculate the molarity of solution

Molarity = number of moles / volume in L

Molarity = 0.299 mol / 1.25 L

Molarity = 0.24 mol/L

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: