Substances x and y are both nonpolar. if the volatility of x is higher than that of y, what is the best explanation? x’s molecules experience stronger dipole-dipole forces than y’s molecules. y’s molecules experience stronger dipole-dipole forces than x’s molecules. x’s molecules experience stronger london dispersion forces than y’s molecules. y’s molecules experience stronger london dispersion forces than x’s molecules.

Substances X and Y are both non polar. If the volatility of X is higher than that of Y, then Y’s molecules experience stronger London dispersion forces than X’s molecules is the best explanation.

Y’s molecules experience stronger London dispersion forces than X’s molecules.

Explanation:

The non polar molecules are bonded by London dispersion force which are the weakest among the other inter-molecular forces. Even though these are the weakest one, this force is sufficient to bind non polar molecules.

The stronger the London dispersion forces, the stronger will be the binding energy of non polar molecules. The volatility is the tendency to get vaporised at room temperature.

So, it is given that X molecules has high volatility. It means that the bond in X molecules can be broken easily compared to the bond strength of Y molecules. This indicates that the molecule of Y experiences stronger London dispersion force than X molecules.

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.