When two hydrogen atoms of mass m combine to form a diatomic hydrogen molecule h2, the potential energy of the system after they combine is โโ, where โ is a positive quantity called the binding energy of the molecule. (a) show that in a collision that involves only two hydrogen atoms, it is impossible to form an h2 molecule because momentum and energy cannot simultaneously be conserved. (hint: if you can show this to be true in one frame of reference, then it is true in all frames of reference. can you see why? ) (b) an h2 molecule can be formed in a collision that involves three hydrogen atoms. suppose that before such a collision, each of the three atoms has speed 3000 m/s , and they are approaching at 120โฆ angles so that at any instant, the atoms lie at the corners of an equilateral triangle. find the speeds of the h2 molecule and of the single hydrogen atom that remains after the collision. the binding energy of h2 is โ = 7.23 ร 10โ19j, and the mass of the hydrogen atom is 1.67 ร 10โ27kg.
Answers: 3
Chemistry, 21.06.2019 21:30, alexandroperez13
It takes 945.kj/mol to break a nitrogen-nitrogen triple bond. calculate the maximum wavelength of light for which a nitrogen-nitrogen triple bond could be broken by absorbing a single photon.
Answers: 3
Chemistry, 22.06.2019 12:30, nekathadon
The bond energy for the van der waals bond between two helium atoms is 7.9ร10โ4ev. assuming that the average kinetic energy of a helium atom is (3/2)kbt, at what temperature is the average kinetic energy equal to the bond energy between two helium atoms
Answers: 1
When two hydrogen atoms of mass m combine to form a diatomic hydrogen molecule h2, the potential ene...