S2 + c > cs2how many grams of cs2 can be prepared by heating 11.0 moles of s2 with excess carbon in 5.20 l reaction vessel held at 900 kelvin until equilibrium is attained? kc= 9.40

Answer : The mass of prepared can be, 754.832 grams

Explanation : Given,

Initial moles of = 11.0 mole

Volume of solution = 5.2 L

Equilibrium constant = 9.40

First we have to calculate the concentration of .

The balanced equilibrium reaction will be,

Initial moles     2.115                    0

At eqm.            (2.115-x)                 x

The equilibrium expression for this reaction will be,

Now put all the given values in this expression, we get:

The concentration of = x = 1.91 M

Now we have to calculate the moles moles of .

Formula used :

Now we have to calculate the mass of .

Therefore, the mass of prepared can be, 754.832 grams

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.