Consider a galvanic cell based on the following two half reactions at 298 k: o ξ cell fe3+ + e- æ fe2+ 0.77 v cu2+ + 2 e- æ cu 0.34 v which of the following changes will increase the potential of the cell? pick the answer that has all correct responses. 1. increasing the concentration of fe+3 ions 2. increasing the concentration of cu2+ ions 3. adding equal volumes of water to both half reactions 4. increasing the concentration of fe2+ ions 5. remove fe2+ ions from solution

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

mark brainliest and have a great day!

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

i believe the answer is 5,000