In this experiment, you will titrate a solution of hcl whose concentration is unknown with a solution of naoh whose concentration is known. based on what you just reviewed, express this goal in the form of an investigative question that you can answer by doing the experiment.

Here we have to get the equation or process by which the unknown concentration of HCl can be determined by the known concentration of NaOH.

The equation to determine the unknown concentration will be ×    = × .

The volume of the HCl or titrant will be known as it will be taken in the conical flask and the volume of the titre i.e. NaOH will be taken in burret.   The indicator used in this titration is phenlopthalien.

At the end point the color of the colorless solution will become light pink and from the burret reading we can get the volume of NaOH required in the titration process.

On plugging the volume, strength of NaOH and volume of HCl, we can obtain the strength of HCl.    

h let me think

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"