The theoretical yield of cl2 from certain starting amounts of mno2 and hcl was calculated as 60.25 g and 65.02 g, respectively. if the percentage yield of cl2 is 72%, what is its actual yield?

The actual yield is 43 g Cl₂.

The limiting reactant was MnO₂ because it gave the smaller mass of Cl₂.

∴ The theoretical yield is 60.25 g Cl₂.

% yield = actual yield/theoretical yield × 100 %

Actual yield = theoretical yield × (% yield/100 %) = 60.25 g × (72 %/100%) = 43 g

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