What pressure is required to achieve a co2 concentration of 7.90×10−2 m at 20∘c?

-  1.90 atm

Solution:- It is based on combined gas law equation, PV = nRT

In this equation, P is pressure, V is volume, n is moles of gas, R is universal gas constant and T is kelvin temperature.

If we divide both sides by V then:

We know that, molarity is moles per liter. So, in the above equation we could replace by molarity, M of the gas. The equation becomes:

P = MRT

T = 20 + 273 = 293 K

M =

Let's plug in the values in the equation:

P =

P = 1.90 atm

So, the pressure of the gas is 1.90 atm.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3